E5D11 - How much real power is consumed in a circuit consisting of a 100-ohm resistor in series with a 100-ohm inductive reactance drawing 1 ampere?

Question

How much real power is consumed in a circuit consisting of a 100-ohm resistor in series with a 100-ohm inductive reactance drawing 1 ampere?

Answer Options

  • A) 70.7 watts
  • B) 100 watts
  • C) 141.4 watts
  • D) 200 watts

Correct Answer: B


Explanation

In an AC circuit containing both resistance and reactance, power is divided into real power (dissipated by the resistance) and reactive power (stored by the reactance). The question asks specifically for the real power consumed, which is only dissipated by the resistor.

Real power is calculated using the formula P_{Real} = I^2 R. Given the current I = 1 \text{ ampere} and the resistance R = 100 \Omega, the real power consumed is P = (1 \text{ A})^2 \times 100 \Omega = 100 \text{ watts}. The inductive reactance (100 \Omega) only consumes reactive power, which is not net power consumed by the entire circuit.


This topic was automatically created to facilitate community discussion about this exam question. Feel free to share study tips, memory tricks, or additional explanations!