Question
What is the peak-to-peak voltage of a sine wave with an RMS voltage of 120 volts?
Answer Options
- A) 84.8 volts
- B) 169.7 volts
- C) 240.0 volts
- D) 339.4 volts
Correct Answer: D
Explanation
For a sine wave, the RMS voltage (V_{\text{RMS}}) is 1 / \sqrt{2} (approximately 0.707) times the peak voltage (V_p). The peak-to-peak voltage (V_{\text{pp}}) is twice the peak voltage: V_{\text{pp}} = 2 V_p. First, find the peak voltage (V_p) using V_p = V_{\text{RMS}} \times \sqrt{2}.
Using V_{\text{RMS}} = 120 \text{ volts}: V_p = 120 \text{ V} \times 1.414 \approx 169.7 \text{ V}. Then, calculate the peak-to-peak voltage: V_{\text{pp}} = 2 V_p = 2 \times 169.7 \text{ V} \approx 339.4 \text{ volts.} The peak-to-peak voltage is 339.4 \text{ volts}.
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