Question
What is the output PEP of 500 volts peak-to-peak across a 50-ohm load?
Answer Options
- A) 8.75 watts
- B) 625 watts
- C) 2500 watts
- D) 5000 watts
Correct Answer: B
Explanation
Peak Envelope Power (PEP) is calculated using the peak voltage (V_p) delivered to the load. First, convert the peak-to-peak voltage (V_{\text{pp}}) to peak voltage (V_p): V_p = V_{\text{pp}} / 2. Next, use the power formula P = V_p^2 / (2R), where R is the load resistance.
Using V_{\text{pp}} = 500 \text{ volts}, V_p = 500 \text{ V} / 2 = 250 \text{ V}. Substituting V_p = 250 \text{ V} and R = 50 \text{ ohms}: P = \frac{V_p^2}{2R} = \frac{(250 \text{ V})^2}{2 \times 50 \text{ }\Omega} = \frac{62500}{100} = 625 \text{ watts.} The output PEP is 625 \text{ watts}.
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