Question
What is the equivalent capacitance of two 5.0-nanofarad capacitors and one 750-picofarad capacitor connected in parallel?
Answer Options
- A) 576.9 nanofarads
- B) 1,733 picofarads
- C) 3,583 picofarads
- D) 10.750 nanofarads
Correct Answer: D
Explanation
For capacitors connected in parallel, the total capacitance (C_T) is the simple sum of the individual capacitances: C_T = C_1 + C_2 + C_3. First, ensure all values are in the same unit. 5.0 \text{ nanofarads} (\text{nF}) is 5,000 \text{ picofarads} (\text{pF}). So, we have 5000 \text{ pF}, 5000 \text{ pF}, and 750 \text{ pF}.
Summing the values: C_T = 5000 \text{ pF} + 5000 \text{ pF} + 750 \text{ pF} = 10,750 \text{ picofarads.} Converting back to nanofarads (1 \text{ nF} = 1000 \text{ pF}), the equivalent capacitance is 10.750 \text{ nanofarads}.
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