Question
How is the efficiency of an RF power amplifier determined?
Answer Options
- A) Divide the DC input power by the DC output power
- B) Divide the RF output power by the DC input power
- C) Multiply the RF input power by the reciprocal of the RF output power
- D) Add the RF input power to the DC output power
Correct Answer: B
Explanation
The efficiency of any power amplifier is a measure of how effectively it converts the DC power supplied by the power source into the desired Radio Frequency (RF) output power. The difference between the two is wasted as heat.
Efficiency is calculated as the ratio of the useful output power to the total input power, expressed as a percentage: \text{Efficiency} = \frac{\text{RF Output Power}}{\text{DC Input Power}} \times 100\% Therefore, efficiency is determined by dividing the RF output power by the DC input power.
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